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Physics Record
Experiment No- 1
Experiment Demonstration of Newton's Third Law
AIM
To prove that the action and reaction never act on the same body but They always act on two different bodies.
OBSERVATIONS ( write on blank page left side)
Number | Spring Balance A | Spring Balance B |
1 | 01 newton | 01 newton |
2 | 02 newton | 02 newton |
3 | 03 newton | 03 newton |
4 | 04 newton | 04 newton |
5 | 05 newton | 05 newton |
APPARATUS
Two Spring Balance
PROCEDURE
The ring of a Spring Balance B is attached to a hook fixed in a wall, and then the hook of another spring balance A is attached to the hook of the spring balance B. Now the ring of spring balance A is pulled. The spring of balance A pulls the spring of the balance A pulls the spring of the balance B due to which we get some reading is seen in balance A because the spring of balance A by the same force. The pull on the spring B by the spring A is the action FBA and the pull on the spring A by the Spring B is the reaction FBA
RESULT
Newton's 3rd Law is verified.
Experiment No: 2
OBSERVATION ( write on blank page left side)
Total number of division on vernier scale = 10
Value of one division on main scale = 1 mm
1 east count = 1/10 = 0.1 mm Zero error = Nil
= 0.01cm.
S NO: | Main Scale Reading a (in cm) | Vernier Division reading b= P*L.C (in cm) | Vernier division coinciding P | Observed length= a+b (in cm) |
1 | 0.8 cm | 0.04 cm | 4 | 0.84 |
2 | 0.8 cm | 0.03 cm | 3 | 0.83 |
3 | 0.8 cm | 0.05 cm | 5 | 0.85 |
4 | 0.8 cm | 0.04 cm | 4 | 0.84 |
VERNIER CALLIPERS
AIM
To measure the length of a metal rope accurately with vernier callipers.
APPARATUS
Vernier callipers, Metal rod
PROCEDURE
1) Find the least count and then the zero error of the vernier callipers if any.
2) Move the Jaw J away form the J and place the object to be measured, between the jaws J and J .
move the jaw J towards the jaw J till it touches the objects. Tighten the screw S to fix the vernier scale in its Position.
3) Note the main scale reading.
4) Note the division P an vernier scale which coincides or is in line with any division o the main scale. Multiply this vernier division P with the least count. This is the vernier scale reading ie, vernier scale reading = P× L C.
5) Add the vernier scale reading to the main scale reading. This gives the observed length.
6) Repeat it three times and record the observations.
RESULT
Length of the given metal rod is 0.84 cm.
EXPERIMENT NO: 3
OBSERVATION ( write on blank page left side)
Pitch of the Screw = 0.1 cm
Total number of divisons on the circular scale = 100
Least count of screw gauge (L.C )
= 0.1 / 100 cm = 0.001cm
Zero error = NIL
S.NO | Main scale reading a(cm) | Circular Scale reading b = no: of division of circular scale in line with the base line P×L.C ( in cm) | Observed diameter = a + b ( in cm ) |
1 | 0.1cm | 13× 0.001 = 0.013 cm | 0.113 |
2 | 0.1cm | 14× 0.001 = 0.014 | 0.114 |
3 | 0.1cm | 15 × 0.001 = 0.015 | 0.115 |
4 | 0.1cm | 16 × 0.001 = 0.016 | 0.116 |
Mean Value = 0.114 cm.
SCREW GUAGE
AIM
To find out the diameter of the given metal wire.
APPARATUS
Screw guage, metal wire
PROCEDURE
1) Find the least count and the zero error ( if any ) of the screw guage.
2) Turn the ratchet anticlockwise so as to obtain a gap between the stud. A and the flat end B. Place the wire in the gap between the stud A and the flat end B. Then turn the ratchet clockwise so as to hold the given wire gently between the stud A and the flat end B of the Screw.
3) Note the main scale reading.
4) Note that division P of the circular scale which coincides with the base line of the main scale. This circular scale division P when multiplied by the least count, gives the circular scale reading i.e. circular scale reading = P × L.C.
5) Add the circular scale reading to the main scale reading to obtain the total reading ( i.e. , the observed diameter of the wise)
6) Repeat it by keeping the wise in perpendicular direction. Take two more observations at different places of the wise and record them in the table below.
RESULT
The diameter of the given wise is observed as 0.114 cm.
EXPERIMENT NO: 4
SIMPLE PENDULUM
AIM
To find the relation between amplitude and time period of a simple pendulum.
APPARATUS
A Bob suspended form a height with cotton thread, Vernier calliper , Stop watch.
PROCEDURE
With the help of vernier callipers find the diameter of Bob and calculate radius. Now setup the pendulum such that the length is 80 cm. Strech the pendulum to one side such that it makes and angle
45° with the mean position.
Release the pendulum at the same time start the stopwatch find the time for 20 oscillation.
OBSERVATION ( write on blank page left side)
SI NO: | Amplitude of pendulum | Time taken for 20 oscillations | Time period of pendulum ( T ) |
01 | 10cm | 245 | 1. 25 |
02 | 15 cm | 246 | 1.25 |
03 | 20 cm | 245 | 1.25 |
RESULT
The time period of a simple pendulum of constant length is independent of amplitude.
EXPERIMENT NO: 5
MEASURING CYLINDER
AIM
To find the volume of a metal bob using a measuring cylinder.
APPARATUS
Metal bob, Measuring cylinder, a fine cotton thread.
PROCEDURE
To find the volume of metal bob power about 15-20 up of water into a clean measuring cylinder. Read and record the initial volume of water. Let it be x . Take a fine cotton thread tie it to the bob. Lower the metal bob gently into the water. Such that, the bob is completely immered in water. Read and Record the new volume of water. Let it be y. Repeat the experiment. So as to obtain three sets of reading.
OBSERVATION ( write on blank page left side)
NO: | Initial Volume (x) | Final Volume (y) | Volume of bob (y-x) |
1 | 18 | 22 | 4 |
2 | 22 | 26 | 4 |
3 | 28 | 32 | 4 |
RESULT
Volume of metal bob = 4cm3
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